You are a lover of bacteria. You want to raise some bacteria in a box. Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly $x$ bacteria in the box at some moment. What is the minimum number of bacteria you need to put into the box across those days? --- 初始时，盒子里是空的。 每天早上，你可以往盒子里放任意数量的细菌。 每天晚上，盒子里的每个细菌都会一分为二。 你希望能在某一时刻，看见盒子里恰好存在 $x$ 个细菌。 问你至少需要往盒子里放多少个细菌？

The only line containing one integer $x$ $(1 \le x \le 10^9)$.

The only line containing one integer: the answer.

For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be $4$ bacteria in the box. Now we put one more resulting $5$ in the box. We added $2$ bacteria in the process so the answer is $2$. For the second sample, we can put one in the first morning and in the $4$-th morning there will be 8 in the box. So the answer is $1$.

Codeforces Div. 2 [CF579A] | 第二届ACC(AcWing Cup)全国联赛