There are $N$ creatures standing in a circle, called Snuke $1, 2, ..., N$ in counter-clockwise order.
When Snuke $i$ $(1 \leq i \leq N)$ receives a gem at time $t$, $S_i$ units of time later, it will hand that gem to Snuke $i+1$ at time $t+S_i$. Here, Snuke $N+1$ is Snuke $1$.
Additionally, Takahashi will hand a gem to Snuke $i$ at time $T_i$.
For each $i$ $(1 \leq i \leq N)$, find the time when Snuke $i$ receives a gem for the first time. Assume that it takes a negligible time to hand a gem.
输入格式
Input is given from Standard Input in the following format:
>$N$\
>$S_1$ $S_2$ $\ldots$ $S_N$\
>$T_1$ $T_2$ $\ldots$ $T_N$
#### Constraints
- $1 \leq N \leq 200000$
- $1 \leq S_i,T_i \leq 10^9$
- All values in input are integers.
输出格式
Print $N$ lines. The $i$\-th line $(1 \leq i \leq N)$ should contain the time when Snuke $i$ receives a gem for the first time.
样例输入 #1
3
4 1 5
3 10 100
样例输出 #1
3
7
8
样例输入 #2
4
100 100 100 100
1 1 1 1
样例输出 #2
1
1
1
1
样例输入 #3
4
1 2 3 4
1 2 4 7
样例输出 #3
1
2
4
7
样例输入 #4
8
84 87 78 16 94 36 87 93
50 22 63 28 91 60 64 27
样例输出 #4
50
22
63
28
44
60
64
27
提示
***For Sample #1:***
We will list the three Snuke's and Takahashi's actions up to time $13$ in chronological order.
Time $3$: Takahashi hands a gem to Snuke $1$.
Time $7$: Snuke $1$ hands a gem to Snuke $2$.
Time $8$: Snuke $2$ hands a gem to Snuke $3$.
Time $10$: Takahashi hands a gem to Snuke $2$.
Time $11$: Snuke $2$ hands a gem to Snuke $3$.
Time $13$: Snuke $3$ hands a gem to Snuke $1$.
After that, they will continue handing gems, though it will be irrelevant to the answer.
***For Sample #2:***
Note that the values $S_i$ and $T_i$ may not be distinct.
***For Sample #3:***
Note that a Snuke may perform multiple transactions simultaneously. Particularly, a Snuke may receive gems simultaneously from Takahashi and another Snuke.